Solve (51/4+4)+11/2

$$( \frac { 51 } { 4 } + 4 ) + 1 \frac { 1 } { 2 }$$

Evaluate

$$\frac{73}{4}=18.25$$

Solution Steps

Convert 4 to fraction \frac{16}{4}.

$$\frac{51}{4}+\frac{16}{4}+\frac{1\times 2+1}{2}$$

Since \frac{51}{4} and \frac{16}{4} have the same denominator, add them by adding their numerators.

$$\frac{51+16}{4}+\frac{1\times 2+1}{2}$$

Add 51 and 16 to get 67.

$$\frac{67}{4}+\frac{1\times 2+1}{2}$$

Multiply 1 and 2 to get 2.

$$\frac{67}{4}+\frac{2+1}{2}$$

Add 2 and 1 to get 3.

$$\frac{67}{4}+\frac{3}{2}$$

Least common multiple of 4 and 2 is 4. Convert \frac{67}{4} and \frac{3}{2} to fractions with denominator 4.

$$\frac{67}{4}+\frac{6}{4}$$

Since \frac{67}{4} and \frac{6}{4} have the same denominator, add them by adding their numerators.

$$\frac{67+6}{4}$$

Add 67 and 6 to get 73.

$$\frac{73}{4}$$

Factor

$$\frac{73}{2 ^ {2}} = 18\frac{1}{4} = 18.25$$