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\frac{\frac{20}{24}-\frac{3}{24}}{\frac{5\times 3+2}{3}}
Least common multiple of 6 and 8 is 24. Convert \frac{5}{6} and \frac{1}{8} to fractions with denominator 24.
\frac{\frac{20-3}{24}}{\frac{5\times 3+2}{3}}
Since \frac{20}{24} and \frac{3}{24} have the same denominator, subtract them by subtracting their numerators.
\frac{\frac{17}{24}}{\frac{5\times 3+2}{3}}
Subtract 3 from 20 to get 17.
\frac{\frac{17}{24}}{\frac{15+2}{3}}
Multiply 5 and 3 to get 15.
\frac{\frac{17}{24}}{\frac{17}{3}}
Add 15 and 2 to get 17.
\frac{17}{24}\times \frac{3}{17}
Divide \frac{17}{24} by \frac{17}{3} by multiplying \frac{17}{24} by the reciprocal of \frac{17}{3}.
\frac{17\times 3}{24\times 17}
Multiply \frac{17}{24} times \frac{3}{17} by multiplying numerator times numerator and denominator times denominator.
\frac{3}{24}
Cancel out 17 in both numerator and denominator.
\frac{1}{8}
Reduce the fraction \frac{3}{24} to lowest terms by extracting and canceling out 3.