Solve (5/3-7)*(7/2-2)=

$$( \frac { 5 } { 3 } - 7 ) \cdot ( \frac { 7 } { 2 } - 2 ) =$$

Evaluate

$$-8$$

Solution Steps

Convert 7 to fraction \frac{21}{3}.

$$\left(\frac{5}{3}-\frac{21}{3}\right)\left(\frac{7}{2}-2\right)$$

Since \frac{5}{3} and \frac{21}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{5-21}{3}\left(\frac{7}{2}-2\right)$$

Subtract 21 from 5 to get -16.

$$-\frac{16}{3}\left(\frac{7}{2}-2\right)$$

Convert 2 to fraction \frac{4}{2}.

$$-\frac{16}{3}\left(\frac{7}{2}-\frac{4}{2}\right)$$

Since \frac{7}{2} and \frac{4}{2} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{16}{3}\times \frac{7-4}{2}$$

Subtract 4 from 7 to get 3.

$$-\frac{16}{3}\times \frac{3}{2}$$

Multiply -\frac{16}{3} times \frac{3}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-16\times 3}{3\times 2}$$

Cancel out 3 in both numerator and denominator.

$$\frac{-16}{2}$$

Divide -16 by 2 to get -8.

$$-8$$

Factor

$$-8$$