Solve (4/9*3/5)+(9*3/4)

$$( \frac { 4 } { 9 } \times \frac { 3 } { 5 } ) + ( 9 \times \frac { 3 } { 4 } )$$

Evaluate

$$\frac{421}{60}\approx 7.016666667$$

Solution Steps

Multiply \frac{4}{9} times \frac{3}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{4\times 3}{9\times 5}+9\times \frac{3}{4}$$

Do the multiplications in the fraction \frac{4\times 3}{9\times 5}.

$$\frac{12}{45}+9\times \frac{3}{4}$$

Reduce the fraction \frac{12}{45} to lowest terms by extracting and canceling out 3.

$$\frac{4}{15}+9\times \frac{3}{4}$$

Express 9\times \frac{3}{4} as a single fraction.

$$\frac{4}{15}+\frac{9\times 3}{4}$$

Multiply 9 and 3 to get 27.

$$\frac{4}{15}+\frac{27}{4}$$

Least common multiple of 15 and 4 is 60. Convert \frac{4}{15} and \frac{27}{4} to fractions with denominator 60.

$$\frac{16}{60}+\frac{405}{60}$$

Since \frac{16}{60} and \frac{405}{60} have the same denominator, add them by adding their numerators.

$$\frac{16+405}{60}$$

Add 16 and 405 to get 421.

$$\frac{421}{60}$$

Factor

$$\frac{421}{2 ^ {2} \cdot 3 \cdot 5} = 7\frac{1}{60} = 7.016666666666667$$