Solve (4/5-1/8)+(16-013)

$$( \frac { 4 } { 5 } - \frac { 1 } { 8 } ) + ( 16 - 013 )$$

Evaluate

$$\frac{667}{40}=16.675$$

Solution Steps

Least common multiple of 5 and 8 is 40. Convert \frac{4}{5} and \frac{1}{8} to fractions with denominator 40.

$$\frac{32}{40}-\frac{5}{40}+16-0\times 13$$

Since \frac{32}{40} and \frac{5}{40} have the same denominator, subtract them by subtracting their numerators.

$$\frac{32-5}{40}+16-0\times 13$$

Subtract 5 from 32 to get 27.

$$\frac{27}{40}+16-0\times 13$$

Multiply 0 and 13 to get 0.

$$\frac{27}{40}+16-0$$

Subtract 0 from 16 to get 16.

$$\frac{27}{40}+16$$

Convert 16 to fraction \frac{640}{40}.

$$\frac{27}{40}+\frac{640}{40}$$

Since \frac{27}{40} and \frac{640}{40} have the same denominator, add them by adding their numerators.

$$\frac{27+640}{40}$$

Add 27 and 640 to get 667.

$$\frac{667}{40}$$

Factor

$$\frac{23 \cdot 29}{2 ^ {3} \cdot 5} = 16\frac{27}{40} = 16.675$$