Solve (4/5-1/8)+(1.6-0.13)

$$( \frac { 4 } { 5 } - \frac { 1 } { 8 } ) + ( 1.6 - 0.13 )$$

Evaluate

$$2.145$$

Solution Steps

Least common multiple of 5 and 8 is 40. Convert \frac{4}{5} and \frac{1}{8} to fractions with denominator 40.

$$\frac{32}{40}-\frac{5}{40}+1.6-0.13$$

Since \frac{32}{40} and \frac{5}{40} have the same denominator, subtract them by subtracting their numerators.

$$\frac{32-5}{40}+1.6-0.13$$

Subtract 5 from 32 to get 27.

$$\frac{27}{40}+1.6-0.13$$

Convert decimal number 1.6 to fraction \frac{16}{10}. Reduce the fraction \frac{16}{10} to lowest terms by extracting and canceling out 2.

$$\frac{27}{40}+\frac{8}{5}-0.13$$

Least common multiple of 40 and 5 is 40. Convert \frac{27}{40} and \frac{8}{5} to fractions with denominator 40.

$$\frac{27}{40}+\frac{64}{40}-0.13$$

Since \frac{27}{40} and \frac{64}{40} have the same denominator, add them by adding their numerators.

$$\frac{27+64}{40}-0.13$$

Add 27 and 64 to get 91.

$$\frac{91}{40}-0.13$$

Convert decimal number 0.13 to fraction \frac{13}{100}.

$$\frac{91}{40}-\frac{13}{100}$$

Least common multiple of 40 and 100 is 200. Convert \frac{91}{40} and \frac{13}{100} to fractions with denominator 200.

$$\frac{455}{200}-\frac{26}{200}$$

Since \frac{455}{200} and \frac{26}{200} have the same denominator, subtract them by subtracting their numerators.

$$\frac{455-26}{200}$$

Subtract 26 from 455 to get 429.

$$\frac{429}{200}$$

Factor

$$\frac{3 \cdot 11 \cdot 13}{2 ^ {3} \cdot 5 ^ {2}} = 2\frac{29}{200} = 2.145$$