Solve (4/5)^2-3*(4/5)=

$$( \frac { 4 } { 5 } ) ^ { 2 } - 3 \cdot ( \frac { 4 } { 5 } ) =$$

Evaluate

$$-\frac{44}{25}=-1.76$$

Solution Steps

Calculate \frac{4}{5} to the power of 2 and get \frac{16}{25}.

$$\frac{16}{25}-3\times \frac{4}{5}$$

Express 3\times \frac{4}{5} as a single fraction.

$$\frac{16}{25}-\frac{3\times 4}{5}$$

Multiply 3 and 4 to get 12.

$$\frac{16}{25}-\frac{12}{5}$$

Least common multiple of 25 and 5 is 25. Convert \frac{16}{25} and \frac{12}{5} to fractions with denominator 25.

$$\frac{16}{25}-\frac{60}{25}$$

Since \frac{16}{25} and \frac{60}{25} have the same denominator, subtract them by subtracting their numerators.

$$\frac{16-60}{25}$$

Subtract 60 from 16 to get -44.

$$-\frac{44}{25}$$

Factor

$$-\frac{44}{25} = -1\frac{19}{25} = -1.76$$