Solve (4/5+1/3)div7/8

$$( \frac { 4 } { 5 } + \frac { 1 } { 3 } ) \div \frac { 7 } { 8 }$$

Evaluate

$$\frac{136}{105}\approx 1.295238095$$

Solution Steps

Least common multiple of 5 and 3 is 15. Convert \frac{4}{5} and \frac{1}{3} to fractions with denominator 15.

$$\frac{\frac{12}{15}+\frac{5}{15}}{\frac{7}{8}}$$

Since \frac{12}{15} and \frac{5}{15} have the same denominator, add them by adding their numerators.

$$\frac{\frac{12+5}{15}}{\frac{7}{8}}$$

Add 12 and 5 to get 17.

$$\frac{\frac{17}{15}}{\frac{7}{8}}$$

Divide \frac{17}{15} by \frac{7}{8} by multiplying \frac{17}{15} by the reciprocal of \frac{7}{8}.

$$\frac{17}{15}\times \frac{8}{7}$$

Multiply \frac{17}{15} times \frac{8}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{17\times 8}{15\times 7}$$

Do the multiplications in the fraction \frac{17\times 8}{15\times 7}.

$$\frac{136}{105}$$

Factor

$$\frac{2 ^ {3} \cdot 17}{3 \cdot 5 \cdot 7} = 1\frac{31}{105} = 1.2952380952380953$$