Solve (4/3)^2-7/2-5/18

$$( \frac { 4 } { 3 } ) ^ { 2 } - \frac { 7 } { 2 } - \frac { 5 } { 18 }$$

Evaluate

$$-2$$

Solution Steps

Calculate \frac{4}{3} to the power of 2 and get \frac{16}{9}.

$$\frac{16}{9}-\frac{7}{2}-\frac{5}{18}$$

Least common multiple of 9 and 2 is 18. Convert \frac{16}{9} and \frac{7}{2} to fractions with denominator 18.

$$\frac{32}{18}-\frac{63}{18}-\frac{5}{18}$$

Since \frac{32}{18} and \frac{63}{18} have the same denominator, subtract them by subtracting their numerators.

$$\frac{32-63}{18}-\frac{5}{18}$$

Subtract 63 from 32 to get -31.

$$-\frac{31}{18}-\frac{5}{18}$$

Since -\frac{31}{18} and \frac{5}{18} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-31-5}{18}$$

Subtract 5 from -31 to get -36.

$$\frac{-36}{18}$$

Divide -36 by 18 to get -2.

$$-2$$

Factor

$$-2$$