Solve (4/3)^2+6(1/2)^2-5/18

$$( \frac { 4 } { 3 } ) ^ { 2 } + 6 ( \frac { 1 } { 2 } ) ^ { 2 } - \frac { 5 } { 18 }$$

Evaluate

$$3$$

Solution Steps

Calculate \frac{4}{3} to the power of 2 and get \frac{16}{9}.

$$\frac{16}{9}+6\times \left(\frac{1}{2}\right)^{2}-\frac{5}{18}$$

Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\frac{16}{9}+6\times \frac{1}{4}-\frac{5}{18}$$

Multiply 6 and \frac{1}{4} to get \frac{6}{4}.

$$\frac{16}{9}+\frac{6}{4}-\frac{5}{18}$$

Reduce the fraction \frac{6}{4} to lowest terms by extracting and canceling out 2.

$$\frac{16}{9}+\frac{3}{2}-\frac{5}{18}$$

Least common multiple of 9 and 2 is 18. Convert \frac{16}{9} and \frac{3}{2} to fractions with denominator 18.

$$\frac{32}{18}+\frac{27}{18}-\frac{5}{18}$$

Since \frac{32}{18} and \frac{27}{18} have the same denominator, add them by adding their numerators.

$$\frac{32+27}{18}-\frac{5}{18}$$

Add 32 and 27 to get 59.

$$\frac{59}{18}-\frac{5}{18}$$

Since \frac{59}{18} and \frac{5}{18} have the same denominator, subtract them by subtracting their numerators.

$$\frac{59-5}{18}$$

Subtract 5 from 59 to get 54.

$$\frac{54}{18}$$

Divide 54 by 18 to get 3.

$$3$$

Factor

$$3$$