Solve (4/3*5/5)+(2/6*4/3)

$$( \frac { 4 } { 3 } \times \frac { 5 } { 5 } ) + ( \frac { 2 } { 6 } \times \frac { 4 } { 3 } )$$

Evaluate

$$\frac{16}{9}\approx 1.777777778$$

Solution Steps

Divide 5 by 5 to get 1.

$$\frac{4}{3}\times 1+\frac{2}{6}\times \frac{4}{3}$$

Multiply \frac{4}{3} and 1 to get \frac{4}{3}.

$$\frac{4}{3}+\frac{2}{6}\times \frac{4}{3}$$

Reduce the fraction \frac{2}{6} to lowest terms by extracting and canceling out 2.

$$\frac{4}{3}+\frac{1}{3}\times \frac{4}{3}$$

Multiply \frac{1}{3} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{4}{3}+\frac{1\times 4}{3\times 3}$$

Do the multiplications in the fraction \frac{1\times 4}{3\times 3}.

$$\frac{4}{3}+\frac{4}{9}$$

Least common multiple of 3 and 9 is 9. Convert \frac{4}{3} and \frac{4}{9} to fractions with denominator 9.

$$\frac{12}{9}+\frac{4}{9}$$

Since \frac{12}{9} and \frac{4}{9} have the same denominator, add them by adding their numerators.

$$\frac{12+4}{9}$$

Add 12 and 4 to get 16.

$$\frac{16}{9}$$

Factor

$$\frac{2 ^ {4}}{3 ^ {2}} = 1\frac{7}{9} = 1.7777777777777777$$