Solve (4/3+1+3/4)y=5

$$( \frac { 4 } { 3 } + 1 + \frac { 3 } { 4 } ) y = 5$$

Solve for y

$$y = \frac{60}{37} = 1\frac{23}{37} \approx 1.621621622$$

Steps for Solving Linear Equation

Convert 1 to fraction \frac{3}{3}.

$$\left(\frac{4}{3}+\frac{3}{3}+\frac{3}{4}\right)y=5$$

Since \frac{4}{3} and \frac{3}{3} have the same denominator, add them by adding their numerators.

$$\left(\frac{4+3}{3}+\frac{3}{4}\right)y=5$$

Add 4 and 3 to get 7.

$$\left(\frac{7}{3}+\frac{3}{4}\right)y=5$$

Least common multiple of 3 and 4 is 12. Convert \frac{7}{3} and \frac{3}{4} to fractions with denominator 12.

$$\left(\frac{28}{12}+\frac{9}{12}\right)y=5$$

Since \frac{28}{12} and \frac{9}{12} have the same denominator, add them by adding their numerators.

$$\frac{28+9}{12}y=5$$

Add 28 and 9 to get 37.

$$\frac{37}{12}y=5$$

Multiply both sides by \frac{12}{37}, the reciprocal of \frac{37}{12}.

$$y=5\times \frac{12}{37}$$

Express 5\times \frac{12}{37} as a single fraction.

$$y=\frac{5\times 12}{37}$$

Multiply 5 and 12 to get 60.

$$y=\frac{60}{37}$$