Solve (4/3+5/2)+7/5=

$$( \frac { 4 } { 3 } + \frac { 5 } { 2 } ) + \frac { 7 } { 5 } =$$

Evaluate

$$\frac{157}{30}\approx 5.233333333$$

Solution Steps

Least common multiple of 3 and 2 is 6. Convert \frac{4}{3} and \frac{5}{2} to fractions with denominator 6.

$$\frac{8}{6}+\frac{15}{6}+\frac{7}{5}$$

Since \frac{8}{6} and \frac{15}{6} have the same denominator, add them by adding their numerators.

$$\frac{8+15}{6}+\frac{7}{5}$$

Add 8 and 15 to get 23.

$$\frac{23}{6}+\frac{7}{5}$$

Least common multiple of 6 and 5 is 30. Convert \frac{23}{6} and \frac{7}{5} to fractions with denominator 30.

$$\frac{115}{30}+\frac{42}{30}$$

Since \frac{115}{30} and \frac{42}{30} have the same denominator, add them by adding their numerators.

$$\frac{115+42}{30}$$

Add 115 and 42 to get 157.

$$\frac{157}{30}$$

Factor

$$\frac{157}{2 \cdot 3 \cdot 5} = 5\frac{7}{30} = 5.233333333333333$$