Solve (4*7/10-7)*(7/10)+3

$$( \frac { 4 \times 7 } { 10 } - 7 ) \times ( \frac { 7 } { 10 } ) + 3$$

Evaluate

$$\frac{3}{50}=0.06$$

Solution Steps

Multiply 4 and 7 to get 28.

$$\left(\frac{28}{10}-7\right)\times \frac{7}{10}+3$$

Reduce the fraction \frac{28}{10} to lowest terms by extracting and canceling out 2.

$$\left(\frac{14}{5}-7\right)\times \frac{7}{10}+3$$

Convert 7 to fraction \frac{35}{5}.

$$\left(\frac{14}{5}-\frac{35}{5}\right)\times \frac{7}{10}+3$$

Since \frac{14}{5} and \frac{35}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{14-35}{5}\times \frac{7}{10}+3$$

Subtract 35 from 14 to get -21.

$$-\frac{21}{5}\times \frac{7}{10}+3$$

Multiply -\frac{21}{5} times \frac{7}{10} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-21\times 7}{5\times 10}+3$$

Do the multiplications in the fraction \frac{-21\times 7}{5\times 10}.

$$\frac{-147}{50}+3$$

Fraction \frac{-147}{50} can be rewritten as -\frac{147}{50} by extracting the negative sign.

$$-\frac{147}{50}+3$$

Convert 3 to fraction \frac{150}{50}.

$$-\frac{147}{50}+\frac{150}{50}$$

Since -\frac{147}{50} and \frac{150}{50} have the same denominator, add them by adding their numerators.

$$\frac{-147+150}{50}$$

Add -147 and 150 to get 3.

$$\frac{3}{50}$$

Factor

$$\frac{3}{2 \cdot 5 ^ {2}} = 0.06$$