Solve (3/9+1)div3/4=

$$( \frac { 3 } { 9 } + 1 ) \div \frac { 3 } { 4 } =$$

Evaluate

$$\frac{16}{9}\approx 1.777777778$$

Solution Steps

Reduce the fraction \frac{3}{9} to lowest terms by extracting and canceling out 3.

$$\frac{\frac{1}{3}+1}{\frac{3}{4}}$$

Convert 1 to fraction \frac{3}{3}.

$$\frac{\frac{1}{3}+\frac{3}{3}}{\frac{3}{4}}$$

Since \frac{1}{3} and \frac{3}{3} have the same denominator, add them by adding their numerators.

$$\frac{\frac{1+3}{3}}{\frac{3}{4}}$$

Add 1 and 3 to get 4.

$$\frac{\frac{4}{3}}{\frac{3}{4}}$$

Divide \frac{4}{3} by \frac{3}{4} by multiplying \frac{4}{3} by the reciprocal of \frac{3}{4}.

$$\frac{4}{3}\times \frac{4}{3}$$

Multiply \frac{4}{3} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{4\times 4}{3\times 3}$$

Do the multiplications in the fraction \frac{4\times 4}{3\times 3}.

$$\frac{16}{9}$$

Factor

$$\frac{2 ^ {4}}{3 ^ {2}} = 1\frac{7}{9} = 1.7777777777777777$$