Solve (3/8-15/9)*3/10=

$$( \frac { 3 } { 8 } - \frac { 15 } { 9 } ) \times \frac { 3 } { 10 } =$$

Evaluate

$$-\frac{31}{80}=-0.3875$$

Solution Steps

Reduce the fraction \frac{15}{9} to lowest terms by extracting and canceling out 3.

$$\left(\frac{3}{8}-\frac{5}{3}\right)\times \frac{3}{10}$$

Least common multiple of 8 and 3 is 24. Convert \frac{3}{8} and \frac{5}{3} to fractions with denominator 24.

$$\left(\frac{9}{24}-\frac{40}{24}\right)\times \frac{3}{10}$$

Since \frac{9}{24} and \frac{40}{24} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-40}{24}\times \frac{3}{10}$$

Subtract 40 from 9 to get -31.

$$-\frac{31}{24}\times \frac{3}{10}$$

Multiply -\frac{31}{24} times \frac{3}{10} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-31\times 3}{24\times 10}$$

Do the multiplications in the fraction \frac{-31\times 3}{24\times 10}.

$$\frac{-93}{240}$$

Reduce the fraction \frac{-93}{240} to lowest terms by extracting and canceling out 3.

$$-\frac{31}{80}$$

Factor

$$-\frac{31}{80} = -0.3875$$