Solve (3/7+5/2):1/7=

$$( \frac { 3 } { 7 } + \frac { 5 } { 2 } ) : \frac { 1 } { 7 } =$$

Evaluate

$$\frac{41}{2}=20.5$$

Solution Steps

Least common multiple of 7 and 2 is 14. Convert \frac{3}{7} and \frac{5}{2} to fractions with denominator 14.

$$\frac{\frac{6}{14}+\frac{35}{14}}{\frac{1}{7}}$$

Since \frac{6}{14} and \frac{35}{14} have the same denominator, add them by adding their numerators.

$$\frac{\frac{6+35}{14}}{\frac{1}{7}}$$

Add 6 and 35 to get 41.

$$\frac{\frac{41}{14}}{\frac{1}{7}}$$

Divide \frac{41}{14} by \frac{1}{7} by multiplying \frac{41}{14} by the reciprocal of \frac{1}{7}.

$$\frac{41}{14}\times 7$$

Express \frac{41}{14}\times 7 as a single fraction.

$$\frac{41\times 7}{14}$$

Multiply 41 and 7 to get 287.

$$\frac{287}{14}$$

Reduce the fraction \frac{287}{14} to lowest terms by extracting and canceling out 7.

$$\frac{41}{2}$$

Factor

$$\frac{41}{2} = 20\frac{1}{2} = 20.5$$