Solve (3/7+1/6)+12/3

$$( \frac { 3 } { 7 } + \frac { 1 } { 6 } ) + 1 \frac { 2 } { 3 }$$

Evaluate

$$\frac{95}{42}\approx 2.261904762$$

Solution Steps

Least common multiple of 7 and 6 is 42. Convert \frac{3}{7} and \frac{1}{6} to fractions with denominator 42.

$$\frac{18}{42}+\frac{7}{42}+\frac{1\times 3+2}{3}$$

Since \frac{18}{42} and \frac{7}{42} have the same denominator, add them by adding their numerators.

$$\frac{18+7}{42}+\frac{1\times 3+2}{3}$$

Add 18 and 7 to get 25.

$$\frac{25}{42}+\frac{1\times 3+2}{3}$$

Multiply 1 and 3 to get 3.

$$\frac{25}{42}+\frac{3+2}{3}$$

Add 3 and 2 to get 5.

$$\frac{25}{42}+\frac{5}{3}$$

Least common multiple of 42 and 3 is 42. Convert \frac{25}{42} and \frac{5}{3} to fractions with denominator 42.

$$\frac{25}{42}+\frac{70}{42}$$

Since \frac{25}{42} and \frac{70}{42} have the same denominator, add them by adding their numerators.

$$\frac{25+70}{42}$$

Add 25 and 70 to get 95.

$$\frac{95}{42}$$

Factor

$$\frac{5 \cdot 19}{2 \cdot 3 \cdot 7} = 2\frac{11}{42} = 2.261904761904762$$