Solve (3/5x^4+1/2x^2)-(2/5x^4-1/2x^2-3)

$$( \frac { 3 } { 5 } x ^ { 4 } + \frac { 1 } { 2 } x ^ { 2 } ) - ( \frac { 2 } { 5 } x ^ { 4 } - \frac { 1 } { 2 } x ^ { 2 } - 3 )$$

Evaluate

$$\frac{x^{4}}{5}+x^{2}+3$$

Solution Steps

To find the opposite of \frac{2}{5}x^{4}-\frac{1}{2}x^{2}-3, find the opposite of each term.

$$\frac{3}{5}x^{4}+\frac{1}{2}x^{2}-\frac{2}{5}x^{4}+\frac{1}{2}x^{2}+3$$

Combine \frac{3}{5}x^{4} and -\frac{2}{5}x^{4} to get \frac{1}{5}x^{4}.

$$\frac{1}{5}x^{4}+\frac{1}{2}x^{2}+\frac{1}{2}x^{2}+3$$

Combine \frac{1}{2}x^{2} and \frac{1}{2}x^{2} to get x^{2}.

$$\frac{1}{5}x^{4}+x^{2}+3$$

Expand

$$\frac{x^{4}}{5}+x^{2}+3$$

Solution Steps

To find the opposite of \frac{2}{5}x^{4}-\frac{1}{2}x^{2}-3, find the opposite of each term.

$$\frac{3}{5}x^{4}+\frac{1}{2}x^{2}-\frac{2}{5}x^{4}+\frac{1}{2}x^{2}+3$$

Combine \frac{3}{5}x^{4} and -\frac{2}{5}x^{4} to get \frac{1}{5}x^{4}.

$$\frac{1}{5}x^{4}+\frac{1}{2}x^{2}+\frac{1}{2}x^{2}+3$$

Combine \frac{1}{2}x^{2} and \frac{1}{2}x^{2} to get x^{2}.

$$\frac{1}{5}x^{4}+x^{2}+3$$