Solve (3/5-2/10)*(3/5+2/10)=

$$( \frac { 3 } { 5 } - \frac { 2 } { 10 } ) \cdot ( \frac { 3 } { 5 } + \frac { 2 } { 10 } ) =$$

Evaluate

$$\frac{8}{25}=0.32$$

Solution Steps

Reduce the fraction \frac{2}{10} to lowest terms by extracting and canceling out 2.

$$\left(\frac{3}{5}-\frac{1}{5}\right)\left(\frac{3}{5}+\frac{2}{10}\right)$$

Since \frac{3}{5} and \frac{1}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-1}{5}\left(\frac{3}{5}+\frac{2}{10}\right)$$

Subtract 1 from 3 to get 2.

$$\frac{2}{5}\left(\frac{3}{5}+\frac{2}{10}\right)$$

Reduce the fraction \frac{2}{10} to lowest terms by extracting and canceling out 2.

$$\frac{2}{5}\left(\frac{3}{5}+\frac{1}{5}\right)$$

Since \frac{3}{5} and \frac{1}{5} have the same denominator, add them by adding their numerators.

$$\frac{2}{5}\times \frac{3+1}{5}$$

Add 3 and 1 to get 4.

$$\frac{2}{5}\times \frac{4}{5}$$

Multiply \frac{2}{5} times \frac{4}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2\times 4}{5\times 5}$$

Do the multiplications in the fraction \frac{2\times 4}{5\times 5}.

$$\frac{8}{25}$$

Factor

$$\frac{2 ^ {3}}{5 ^ {2}} = 0.32$$