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\left(\frac{3}{5}\right)^{12}=\left(\frac{3}{5}\right)^{3x}
To multiply powers of the same base, add their exponents. Add 6 and 6 to get 12.
\frac{531441}{244140625}=\left(\frac{3}{5}\right)^{3x}
Calculate \frac{3}{5} to the power of 12 and get \frac{531441}{244140625}.
\left(\frac{3}{5}\right)^{3x}=\frac{531441}{244140625}
Swap sides so that all variable terms are on the left hand side.
\log(\left(\frac{3}{5}\right)^{3x})=\log(\frac{531441}{244140625})
Take the logarithm of both sides of the equation.
3x\log(\frac{3}{5})=\log(\frac{531441}{244140625})
The logarithm of a number raised to a power is the power times the logarithm of the number.
3x=\frac{\log(\frac{531441}{244140625})}{\log(\frac{3}{5})}
Divide both sides by \log(\frac{3}{5}).
3x=\log_{\frac{3}{5}}\left(\frac{531441}{244140625}\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
x=\frac{12}{3}
Divide both sides by 3.