Solve (3/5+1/10)div-14/15

$$( \frac { 3 } { 5 } + \frac { 1 } { 10 } ) \div \frac { - 14 } { 15 }$$

Evaluate

$$-\frac{3}{4}=-0.75$$

Solution Steps

Least common multiple of 5 and 10 is 10. Convert \frac{3}{5} and \frac{1}{10} to fractions with denominator 10.

$$\frac{\frac{6}{10}+\frac{1}{10}}{\frac{-14}{15}}$$

Since \frac{6}{10} and \frac{1}{10} have the same denominator, add them by adding their numerators.

$$\frac{\frac{6+1}{10}}{\frac{-14}{15}}$$

Add 6 and 1 to get 7.

$$\frac{\frac{7}{10}}{\frac{-14}{15}}$$

Fraction \frac{-14}{15} can be rewritten as -\frac{14}{15} by extracting the negative sign.

$$\frac{\frac{7}{10}}{-\frac{14}{15}}$$

Divide \frac{7}{10} by -\frac{14}{15} by multiplying \frac{7}{10} by the reciprocal of -\frac{14}{15}.

$$\frac{7}{10}\left(-\frac{15}{14}\right)$$

Multiply \frac{7}{10} times -\frac{15}{14} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7\left(-15\right)}{10\times 14}$$

Do the multiplications in the fraction \frac{7\left(-15\right)}{10\times 14}.

$$\frac{-105}{140}$$

Reduce the fraction \frac{-105}{140} to lowest terms by extracting and canceling out 35.

$$-\frac{3}{4}$$

Factor

$$-\frac{3}{4} = -0.75$$