Solve (3/4y+1)*4=3

$$( \frac { 3 } { 4 } y + 1 ) \cdot 4 = 3$$

Solve for y

$$y=-\frac{1}{3}\approx -0.333333333$$

Steps for Solving Linear Equation

Divide both sides by 4.

$$\frac{3}{4}y+1=\frac{3}{4}$$

Subtract 1 from both sides.

$$\frac{3}{4}y=\frac{3}{4}-1$$

Convert 1 to fraction \frac{4}{4}.

$$\frac{3}{4}y=\frac{3}{4}-\frac{4}{4}$$

Since \frac{3}{4} and \frac{4}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3}{4}y=\frac{3-4}{4}$$

Subtract 4 from 3 to get -1.

$$\frac{3}{4}y=-\frac{1}{4}$$

Multiply both sides by \frac{4}{3}, the reciprocal of \frac{3}{4}.

$$y=-\frac{1}{4}\times \frac{4}{3}$$

Multiply -\frac{1}{4} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$y=\frac{-4}{4\times 3}$$

Cancel out 4 in both numerator and denominator.

$$y=\frac{-1}{3}$$

Fraction \frac{-1}{3} can be rewritten as -\frac{1}{3} by extracting the negative sign.

$$y=-\frac{1}{3}$$