Solve (3/4+1/2)+(11/4)^2

$$( \frac { 3 } { 4 } + \frac { 1 } { 2 } ) + ( 1 \frac { 1 } { 4 } ) ^ { 2 }$$

Evaluate

$$\frac{45}{16}=2.8125$$

Solution Steps

Add \frac{3}{4} and \frac{1}{2} to get \frac{5}{4}.

$$\frac{5}{4}+\left(\frac{1\times 4+1}{4}\right)^{2}$$

Multiply 1 and 4 to get 4.

$$\frac{5}{4}+\left(\frac{4+1}{4}\right)^{2}$$

Add 4 and 1 to get 5.

$$\frac{5}{4}+\left(\frac{5}{4}\right)^{2}$$

Calculate \frac{5}{4} to the power of 2 and get \frac{25}{16}.

$$\frac{5}{4}+\frac{25}{16}$$

Add \frac{5}{4} and \frac{25}{16} to get \frac{45}{16}.

$$\frac{45}{16}$$

Factor

$$\frac{3 ^ {2} \cdot 5}{2 ^ {4}} = 2\frac{13}{16} = 2.8125$$