Solve (3/20+7/30)*15

$$( \frac { 3 } { 20 } + \frac { 7 } { 30 } ) \cdot 15$$

Evaluate

$$\frac{23}{4}=5.75$$

Solution Steps

Least common multiple of 20 and 30 is 60. Convert \frac{3}{20} and \frac{7}{30} to fractions with denominator 60.

$$\left(\frac{9}{60}+\frac{14}{60}\right)\times 15$$

Since \frac{9}{60} and \frac{14}{60} have the same denominator, add them by adding their numerators.

$$\frac{9+14}{60}\times 15$$

Add 9 and 14 to get 23.

$$\frac{23}{60}\times 15$$

Express \frac{23}{60}\times 15 as a single fraction.

$$\frac{23\times 15}{60}$$

Multiply 23 and 15 to get 345.

$$\frac{345}{60}$$

Reduce the fraction \frac{345}{60} to lowest terms by extracting and canceling out 15.

$$\frac{23}{4}$$

Factor

$$\frac{23}{2 ^ {2}} = 5\frac{3}{4} = 5.75$$