Solve (3/2)^2-(-1div0.2)+(-3)*5/12

$$( \frac { 3 } { 2 } ) ^ { 2 } - ( - 1 \div 0.2 ) + ( - 3 ) \times \frac { 5 } { 12 }$$

Evaluate

$$6$$

Solution Steps

Calculate \frac{3}{2} to the power of 2 and get \frac{9}{4}.

$$\frac{9}{4}-\frac{-1}{0.2}-3\times \frac{5}{12}$$

Expand \frac{-1}{0.2} by multiplying both numerator and the denominator by 10.

$$\frac{9}{4}-\frac{-10}{2}-3\times \frac{5}{12}$$

Divide -10 by 2 to get -5.

$$\frac{9}{4}-\left(-5\right)-3\times \frac{5}{12}$$

The opposite of -5 is 5.

$$\frac{9}{4}+5-3\times \frac{5}{12}$$

Convert 5 to fraction \frac{20}{4}.

$$\frac{9}{4}+\frac{20}{4}-3\times \frac{5}{12}$$

Since \frac{9}{4} and \frac{20}{4} have the same denominator, add them by adding their numerators.

$$\frac{9+20}{4}-3\times \frac{5}{12}$$

Add 9 and 20 to get 29.

$$\frac{29}{4}-3\times \frac{5}{12}$$

Express -3\times \frac{5}{12} as a single fraction.

$$\frac{29}{4}+\frac{-3\times 5}{12}$$

Multiply -3 and 5 to get -15.

$$\frac{29}{4}+\frac{-15}{12}$$

Reduce the fraction \frac{-15}{12} to lowest terms by extracting and canceling out 3.

$$\frac{29}{4}-\frac{5}{4}$$

Since \frac{29}{4} and \frac{5}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{29-5}{4}$$

Subtract 5 from 29 to get 24.

$$\frac{24}{4}$$

Divide 24 by 4 to get 6.

$$6$$

Factor

$$2\times 3$$