Solve (3^3/3)-(-1^3/3)

$$( \frac { 3 ^ { 3 } } { 3 } ) - ( \frac { - 1 ^ { 3 } } { 3 } )$$

Evaluate

$$\frac{28}{3}\approx 9.333333333$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 1 from 3 to get 2.

$$3^{2}-\frac{-1^{3}}{3}$$

Calculate 3 to the power of 2 and get 9.

$$9-\frac{-1^{3}}{3}$$

Calculate 1 to the power of 3 and get 1.

$$9-\frac{-1}{3}$$

Fraction \frac{-1}{3} can be rewritten as -\frac{1}{3} by extracting the negative sign.

$$9-\left(-\frac{1}{3}\right)$$

The opposite of -\frac{1}{3} is \frac{1}{3}.

$$9+\frac{1}{3}$$

Convert 9 to fraction \frac{27}{3}.

$$\frac{27}{3}+\frac{1}{3}$$

Since \frac{27}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$\frac{27+1}{3}$$

Add 27 and 1 to get 28.

$$\frac{28}{3}$$

Factor

$$\frac{2 ^ {2} \cdot 7}{3} = 9\frac{1}{3} = 9.333333333333334$$