Solve (23/46+114/57+94/47+37/74)^2=

$$( \frac { 23 } { 46 } + \frac { 114 } { 57 } + \frac { 94 } { 47 } + \frac { 37 } { 74 } ) ^ { 2 } =$$

Evaluate

$$25$$

Solution Steps

Reduce the fraction \frac{23}{46} to lowest terms by extracting and canceling out 23.

$$\left(\frac{1}{2}+\frac{114}{57}+\frac{94}{47}+\frac{37}{74}\right)^{2}$$

Divide 114 by 57 to get 2.

$$\left(\frac{1}{2}+2+\frac{94}{47}+\frac{37}{74}\right)^{2}$$

Add \frac{1}{2} and 2 to get \frac{5}{2}.

$$\left(\frac{5}{2}+\frac{94}{47}+\frac{37}{74}\right)^{2}$$

Divide 94 by 47 to get 2.

$$\left(\frac{5}{2}+2+\frac{37}{74}\right)^{2}$$

Add \frac{5}{2} and 2 to get \frac{9}{2}.

$$\left(\frac{9}{2}+\frac{37}{74}\right)^{2}$$

Reduce the fraction \frac{37}{74} to lowest terms by extracting and canceling out 37.

$$\left(\frac{9}{2}+\frac{1}{2}\right)^{2}$$

Add \frac{9}{2} and \frac{1}{2} to get 5.

$$5^{2}$$

Calculate 5 to the power of 2 and get 25.

$$25$$

Factor

$$5^{2}$$