Solve (2x/2y^3)^-2

$$( \frac { 2 x } { 2 y ^ { 3 } } ) ^ { - 2 }$$

Evaluate

$$\frac{y^{6}}{x^{2}}$$

Solution Steps

Cancel out 2 in both numerator and denominator.

$$\left(\frac{x}{y^{3}}\right)^{-2}$$

To raise \frac{x}{y^{3}} to a power, raise both numerator and denominator to the power and then divide.

$$\frac{x^{-2}}{\left(y^{3}\right)^{-2}}$$

To raise a power to another power, multiply the exponents. Multiply 3 and -2 to get -6.

$$\frac{x^{-2}}{y^{-6}}$$

Expand

$$\frac{y^{6}}{x^{2}}$$

Solution Steps

Cancel out 2 in both numerator and denominator.

$$\left(\frac{x}{y^{3}}\right)^{-2}$$

To raise \frac{x}{y^{3}} to a power, raise both numerator and denominator to the power and then divide.

$$\frac{x^{-2}}{\left(y^{3}\right)^{-2}}$$

To raise a power to another power, multiply the exponents. Multiply 3 and -2 to get -6.

$$\frac{x^{-2}}{y^{-6}}$$