Solve (2x^3y/-xy^3*-x)

$$( \frac { 2 x ^ { 3 } y } { - x y ^ { 3 } } \cdot - x )$$

Evaluate

$$\frac{2x^{3}}{y^{2}}$$

Short Solution Steps

Cancel out y in both numerator and denominator.

$$\frac{2x^{3}}{\left(-x\right)y^{2}}\left(-x\right)$$

Factor the expressions that are not already factored in \frac{2x^{3}}{\left(-x\right)y^{2}}.

$$\frac{2x^{3}}{-xy^{2}}\left(-x\right)$$

Cancel out x in both numerator and denominator.

$$\frac{2x^{2}}{-y^{2}}\left(-x\right)$$

Cancel out -1 in both numerator and denominator.

$$\frac{-2x^{2}}{y^{2}}\left(-x\right)$$

Express \frac{-2x^{2}}{y^{2}}\left(-x\right) as a single fraction.

$$\frac{-\left(-2\right)x^{2}x}{y^{2}}$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$\frac{-\left(-2\right)x^{3}}{y^{2}}$$

Multiply -1 and -2 to get 2.

$$\frac{2x^{3}}{y^{2}}$$

Differentiate w.r.t. x

$$6\times \left(\frac{x}{y}\right)^{2}$$