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\frac{1}{4}a+\frac{1}{2}=a
Divide each term of 2a+4 by 8 to get \frac{1}{4}a+\frac{1}{2}.
\frac{1}{4}a+\frac{1}{2}-a=0
Subtract a from both sides.
-\frac{3}{4}a+\frac{1}{2}=0
Combine \frac{1}{4}a and -a to get -\frac{3}{4}a.
-\frac{3}{4}a=-\frac{1}{2}
Subtract \frac{1}{2} from both sides. Anything subtracted from zero gives its negation.
a=-\frac{1}{2}\left(-\frac{4}{3}\right)
Multiply both sides by -\frac{4}{3}, the reciprocal of -\frac{3}{4}.
a=\frac{-\left(-4\right)}{2\times 3}
Multiply -\frac{1}{2} times -\frac{4}{3} by multiplying numerator times numerator and denominator times denominator.
a=\frac{4}{6}
Do the multiplications in the fraction \frac{-\left(-4\right)}{2\times 3}.
a=\frac{2}{3}
Reduce the fraction \frac{4}{6} to lowest terms by extracting and canceling out 2.