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\frac{\frac{2}{9}x}{\frac{1}{6}}+\frac{-7}{\frac{1}{6}}-x=126
Divide each term of \frac{2}{9}x-7 by \frac{1}{6} to get \frac{\frac{2}{9}x}{\frac{1}{6}}+\frac{-7}{\frac{1}{6}}.
\frac{4}{3}x+\frac{-7}{\frac{1}{6}}-x=126
Divide \frac{2}{9}x by \frac{1}{6} to get \frac{4}{3}x.
\frac{4}{3}x-7\times 6-x=126
Divide -7 by \frac{1}{6} by multiplying -7 by the reciprocal of \frac{1}{6}.
\frac{4}{3}x-42-x=126
Multiply -7 and 6 to get -42.
\frac{1}{3}x-42=126
Combine \frac{4}{3}x and -x to get \frac{1}{3}x.
\frac{1}{3}x=126+42
Add 42 to both sides.
\frac{1}{3}x=168
Add 126 and 42 to get 168.
x=168\times 3
Multiply both sides by 3, the reciprocal of \frac{1}{3}.
x=504
Multiply 168 and 3 to get 504.