Solve (2/9+1/6)div2/3

$$( \frac { 2 } { 9 } + \frac { 1 } { 6 } ) \div \frac { 2 } { 3 }$$

Evaluate

$$\frac{7}{12}\approx 0.583333333$$

Solution Steps

Least common multiple of 9 and 6 is 18. Convert \frac{2}{9} and \frac{1}{6} to fractions with denominator 18.

$$\frac{\frac{4}{18}+\frac{3}{18}}{\frac{2}{3}}$$

Since \frac{4}{18} and \frac{3}{18} have the same denominator, add them by adding their numerators.

$$\frac{\frac{4+3}{18}}{\frac{2}{3}}$$

Add 4 and 3 to get 7.

$$\frac{\frac{7}{18}}{\frac{2}{3}}$$

Divide \frac{7}{18} by \frac{2}{3} by multiplying \frac{7}{18} by the reciprocal of \frac{2}{3}.

$$\frac{7}{18}\times \frac{3}{2}$$

Multiply \frac{7}{18} times \frac{3}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7\times 3}{18\times 2}$$

Do the multiplications in the fraction \frac{7\times 3}{18\times 2}.

$$\frac{21}{36}$$

Reduce the fraction \frac{21}{36} to lowest terms by extracting and canceling out 3.

$$\frac{7}{12}$$

Factor

$$\frac{7}{2 ^ {2} \cdot 3} = 0.5833333333333334$$