Solve (2/7+4/6)*(20/47)

$$( \frac { 2 } { 7 } + \frac { 4 } { 6 } ) \times ( \frac { 20 } { 47 } )$$

Evaluate

$$\frac{400}{987}\approx 0.40526849$$

Solution Steps

Reduce the fraction \frac{4}{6} to lowest terms by extracting and canceling out 2.

$$\left(\frac{2}{7}+\frac{2}{3}\right)\times \frac{20}{47}$$

Least common multiple of 7 and 3 is 21. Convert \frac{2}{7} and \frac{2}{3} to fractions with denominator 21.

$$\left(\frac{6}{21}+\frac{14}{21}\right)\times \frac{20}{47}$$

Since \frac{6}{21} and \frac{14}{21} have the same denominator, add them by adding their numerators.

$$\frac{6+14}{21}\times \frac{20}{47}$$

Add 6 and 14 to get 20.

$$\frac{20}{21}\times \frac{20}{47}$$

Multiply \frac{20}{21} times \frac{20}{47} by multiplying numerator times numerator and denominator times denominator.

$$\frac{20\times 20}{21\times 47}$$

Do the multiplications in the fraction \frac{20\times 20}{21\times 47}.

$$\frac{400}{987}$$

Factor

$$\frac{2 ^ {4} \cdot 5 ^ {2}}{3 \cdot 7 \cdot 47} = 0.40526849037487334$$