Solve (2/5-5/3)div2/3-(0,1)^0=

$$( \frac { 2 } { 5 } - \frac { 5 } { 3 } ) \div \frac { 2 } { 3 } - ( 0,1 ) ^ { 0 } =$$

Evaluate

$$-2,9$$

Solution Steps

Subtract \frac{5}{3} from \frac{2}{5} to get -\frac{19}{15}.

$$\frac{-\frac{19}{15}}{\frac{2}{3}}-0,1^{0}$$

Divide -\frac{19}{15} by \frac{2}{3} by multiplying -\frac{19}{15} by the reciprocal of \frac{2}{3}.

$$-\frac{19}{15}\times \frac{3}{2}-0,1^{0}$$

Multiply -\frac{19}{15} and \frac{3}{2} to get -\frac{19}{10}.

$$-\frac{19}{10}-0,1^{0}$$

Calculate 0,1 to the power of 0 and get 1.

$$-\frac{19}{10}-1$$

Subtract 1 from -\frac{19}{10} to get -\frac{29}{10}.

$$-\frac{29}{10}$$

Factor

$$-2,9$$