Solve (2/3x^3y)(-4x^2y^3)(-x)

$$( \frac { 2 } { 3 } x ^ { 3 } y ) ( - 4 x ^ { 2 } y ^ { 3 } ) ( - x )$$

Evaluate

$$\frac{8y^{4}x^{6}}{3}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 3 and 2 to get 5.

$$\frac{2}{3}x^{5}y\left(-4\right)y^{3}\left(-x\right)$$

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$\frac{2}{3}x^{5}y^{4}\left(-4\right)\left(-x\right)$$

Multiply \frac{2}{3} and -4 to get -\frac{8}{3}.

$$-\frac{8}{3}x^{5}y^{4}\left(-x\right)$$

Multiply -\frac{8}{3} and -1 to get \frac{8}{3}.

$$\frac{8}{3}x^{5}y^{4}x$$

To multiply powers of the same base, add their exponents. Add 5 and 1 to get 6.

$$\frac{8}{3}x^{6}y^{4}$$

Differentiate w.r.t. x

$$16y^{4}x^{5}$$