Solve (2/3x+1)+1/4=12

$$( \frac { 2 } { 3 } x + 1 ) + \frac { 1 } { 4 } = 12$$

Solve for x

$$x = \frac{129}{8} = 16\frac{1}{8} = 16.125$$

Steps for Solving Linear Equation

Convert 1 to fraction \frac{4}{4}.

$$\frac{2}{3}x+\frac{4}{4}+\frac{1}{4}=12$$

Since \frac{4}{4} and \frac{1}{4} have the same denominator, add them by adding their numerators.

$$\frac{2}{3}x+\frac{4+1}{4}=12$$

Add 4 and 1 to get 5.

$$\frac{2}{3}x+\frac{5}{4}=12$$

Subtract \frac{5}{4} from both sides.

$$\frac{2}{3}x=12-\frac{5}{4}$$

Convert 12 to fraction \frac{48}{4}.

$$\frac{2}{3}x=\frac{48}{4}-\frac{5}{4}$$

Since \frac{48}{4} and \frac{5}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2}{3}x=\frac{48-5}{4}$$

Subtract 5 from 48 to get 43.

$$\frac{2}{3}x=\frac{43}{4}$$

Multiply both sides by \frac{3}{2}, the reciprocal of \frac{2}{3}.

$$x=\frac{43}{4}\times \frac{3}{2}$$

Multiply \frac{43}{4} times \frac{3}{2} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{43\times 3}{4\times 2}$$

Do the multiplications in the fraction \frac{43\times 3}{4\times 2}.

$$x=\frac{129}{8}$$