Solve (2/3-1+4/3)div2

$$( \frac { 2 } { 3 } - 1 + \frac { 4 } { 3 } ) \div 2$$

Evaluate

$$\frac{1}{2}=0.5$$

Solution Steps

Convert 1 to fraction \frac{3}{3}.

$$\frac{\frac{2}{3}-\frac{3}{3}+\frac{4}{3}}{2}$$

Since \frac{2}{3} and \frac{3}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{2-3}{3}+\frac{4}{3}}{2}$$

Subtract 3 from 2 to get -1.

$$\frac{-\frac{1}{3}+\frac{4}{3}}{2}$$

Since -\frac{1}{3} and \frac{4}{3} have the same denominator, add them by adding their numerators.

$$\frac{\frac{-1+4}{3}}{2}$$

Add -1 and 4 to get 3.

$$\frac{\frac{3}{3}}{2}$$

Divide 3 by 3 to get 1.

$$\frac{1}{2}$$

Factor

$$\frac{1}{2} = 0.5$$