Solve (2/3-2/6)^2+3/4=

$$( \frac { 2 } { 3 } - \frac { 2 } { 6 } ) ^ { 2 } + \frac { 3 } { 4 } =$$

Evaluate

$$\frac{31}{36}\approx 0.861111111$$

Solution Steps

Reduce the fraction \frac{2}{6} to lowest terms by extracting and canceling out 2.

$$\left(\frac{2}{3}-\frac{1}{3}\right)^{2}+\frac{3}{4}$$

Subtract \frac{1}{3} from \frac{2}{3} to get \frac{1}{3}.

$$\left(\frac{1}{3}\right)^{2}+\frac{3}{4}$$

Calculate \frac{1}{3} to the power of 2 and get \frac{1}{9}.

$$\frac{1}{9}+\frac{3}{4}$$

Add \frac{1}{9} and \frac{3}{4} to get \frac{31}{36}.

$$\frac{31}{36}$$

Factor

$$\frac{31}{2 ^ {2} \cdot 3 ^ {2}} = 0.8611111111111112$$