Solve (2/3-19/6+05)

$$( \frac { 2 } { 3 } - \frac { 19 } { 6 } + 05 )$$

Evaluate

$$-\frac{5}{2}=-2.5$$

Solution Steps

Least common multiple of 3 and 6 is 6. Convert \frac{2}{3} and \frac{19}{6} to fractions with denominator 6.

$$\frac{4}{6}-\frac{19}{6}+0\times 5$$

Since \frac{4}{6} and \frac{19}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4-19}{6}+0\times 5$$

Subtract 19 from 4 to get -15.

$$\frac{-15}{6}+0\times 5$$

Reduce the fraction \frac{-15}{6} to lowest terms by extracting and canceling out 3.

$$-\frac{5}{2}+0\times 5$$

Multiply 0 and 5 to get 0.

$$-\frac{5}{2}+0$$

Add -\frac{5}{2} and 0 to get -\frac{5}{2}.

$$-\frac{5}{2}$$

Factor

$$-\frac{5}{2} = -2\frac{1}{2} = -2.5$$