Solve (2/3-19/6+0.5)

$$( \frac { 2 } { 3 } - \frac { 19 } { 6 } + 0.5 )$$

Evaluate

$$-2$$

Solution Steps

Least common multiple of 3 and 6 is 6. Convert \frac{2}{3} and \frac{19}{6} to fractions with denominator 6.

$$\frac{4}{6}-\frac{19}{6}+0.5$$

Since \frac{4}{6} and \frac{19}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4-19}{6}+0.5$$

Subtract 19 from 4 to get -15.

$$\frac{-15}{6}+0.5$$

Reduce the fraction \frac{-15}{6} to lowest terms by extracting and canceling out 3.

$$-\frac{5}{2}+0.5$$

Convert decimal number 0.5 to fraction \frac{5}{10}. Reduce the fraction \frac{5}{10} to lowest terms by extracting and canceling out 5.

$$-\frac{5}{2}+\frac{1}{2}$$

Since -\frac{5}{2} and \frac{1}{2} have the same denominator, add them by adding their numerators.

$$\frac{-5+1}{2}$$

Add -5 and 1 to get -4.

$$\frac{-4}{2}$$

Divide -4 by 2 to get -2.

$$-2$$

Factor

$$-2$$