Solve (2/3)(7/4)(-12/21)=

$$( \frac { 2 } { 3 } ) ( \frac { 7 } { 4 } ) ( - \frac { 12 } { 21 } ) =$$

Evaluate

$$-\frac{2}{3}\approx -0.666666667$$

Solution Steps

Multiply \frac{2}{3} times \frac{7}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2\times 7}{3\times 4}\left(-\frac{12}{21}\right)$$

Do the multiplications in the fraction \frac{2\times 7}{3\times 4}.

$$\frac{14}{12}\left(-\frac{12}{21}\right)$$

Reduce the fraction \frac{14}{12} to lowest terms by extracting and canceling out 2.

$$\frac{7}{6}\left(-\frac{12}{21}\right)$$

Reduce the fraction \frac{12}{21} to lowest terms by extracting and canceling out 3.

$$\frac{7}{6}\left(-\frac{4}{7}\right)$$

Multiply \frac{7}{6} times -\frac{4}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7\left(-4\right)}{6\times 7}$$

Cancel out 7 in both numerator and denominator.

$$\frac{-4}{6}$$

Reduce the fraction \frac{-4}{6} to lowest terms by extracting and canceling out 2.

$$-\frac{2}{3}$$

Factor

$$-\frac{2}{3} = -0.6666666666666666$$