Solve (2/3)(4/7)(2/8)(31/3)=

$$( \frac { 2 } { 3 } ) ( \frac { 4 } { 7 } ) ( \frac { 2 } { 8 } ) ( \frac { 31 } { 3 } ) =$$

Evaluate

$$\frac{62}{63}\approx 0.984126984$$

Solution Steps

Multiply \frac{2}{3} times \frac{4}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2\times 4}{3\times 7}\times \frac{2}{8}\times \frac{31}{3}$$

Do the multiplications in the fraction \frac{2\times 4}{3\times 7}.

$$\frac{8}{21}\times \frac{2}{8}\times \frac{31}{3}$$

Reduce the fraction \frac{2}{8} to lowest terms by extracting and canceling out 2.

$$\frac{8}{21}\times \frac{1}{4}\times \frac{31}{3}$$

Multiply \frac{8}{21} times \frac{1}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{8\times 1}{21\times 4}\times \frac{31}{3}$$

Do the multiplications in the fraction \frac{8\times 1}{21\times 4}.

$$\frac{8}{84}\times \frac{31}{3}$$

Reduce the fraction \frac{8}{84} to lowest terms by extracting and canceling out 4.

$$\frac{2}{21}\times \frac{31}{3}$$

Multiply \frac{2}{21} times \frac{31}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2\times 31}{21\times 3}$$

Do the multiplications in the fraction \frac{2\times 31}{21\times 3}.

$$\frac{62}{63}$$

Factor

$$\frac{2 \cdot 31}{3 ^ {2} \cdot 7} = 0.9841269841269841$$