Solve (2/3)^3*(1/6)^3

$$( \frac { 2 } { 3 } ) ^ { 3 } \times ( \frac { 1 } { 6 } ) ^ { 3 }$$

Evaluate

$$\frac{1}{729}\approx 0.001371742$$

Solution Steps

Calculate \frac{2}{3} to the power of 3 and get \frac{8}{27}.

$$\frac{8}{27}\times \left(\frac{1}{6}\right)^{3}$$

Calculate \frac{1}{6} to the power of 3 and get \frac{1}{216}.

$$\frac{8}{27}\times \frac{1}{216}$$

Multiply \frac{8}{27} times \frac{1}{216} by multiplying numerator times numerator and denominator times denominator.

$$\frac{8\times 1}{27\times 216}$$

Do the multiplications in the fraction \frac{8\times 1}{27\times 216}.

$$\frac{8}{5832}$$

Reduce the fraction \frac{8}{5832} to lowest terms by extracting and canceling out 8.

$$\frac{1}{729}$$

Factor

$$\frac{1}{3 ^ {6}} = 0.0013717421124828531$$