Solve (2/3)^2+12/27

$$( \frac { 2 } { 3 } ) ^ { 2 } + 1 \frac { 2 } { 27 }$$

Evaluate

$$\frac{41}{27}\approx 1.518518519$$

Solution Steps

Calculate \frac{2}{3} to the power of 2 and get \frac{4}{9}.

$$\frac{4}{9}+\frac{1\times 27+2}{27}$$

Multiply 1 and 27 to get 27.

$$\frac{4}{9}+\frac{27+2}{27}$$

Add 27 and 2 to get 29.

$$\frac{4}{9}+\frac{29}{27}$$

Least common multiple of 9 and 27 is 27. Convert \frac{4}{9} and \frac{29}{27} to fractions with denominator 27.

$$\frac{12}{27}+\frac{29}{27}$$

Since \frac{12}{27} and \frac{29}{27} have the same denominator, add them by adding their numerators.

$$\frac{12+29}{27}$$

Add 12 and 29 to get 41.

$$\frac{41}{27}$$

Factor

$$\frac{41}{3 ^ {3}} = 1\frac{14}{27} = 1.5185185185185186$$