Solve (2/3)^2+1/3*3/5

$$( \frac { 2 } { 3 } ) ^ { 2 } + \frac { 1 } { 3 } \cdot \frac { 3 } { 5 }$$

Evaluate

$$\frac{29}{45}\approx 0.644444444$$

Solution Steps

Calculate \frac{2}{3} to the power of 2 and get \frac{4}{9}.

$$\frac{4}{9}+\frac{1}{3}\times \frac{3}{5}$$

Multiply \frac{1}{3} times \frac{3}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{4}{9}+\frac{1\times 3}{3\times 5}$$

Cancel out 3 in both numerator and denominator.

$$\frac{4}{9}+\frac{1}{5}$$

Least common multiple of 9 and 5 is 45. Convert \frac{4}{9} and \frac{1}{5} to fractions with denominator 45.

$$\frac{20}{45}+\frac{9}{45}$$

Since \frac{20}{45} and \frac{9}{45} have the same denominator, add them by adding their numerators.

$$\frac{20+9}{45}$$

Add 20 and 9 to get 29.

$$\frac{29}{45}$$

Factor

$$\frac{29}{3 ^ {2} \cdot 5} = 0.6444444444444445$$