Solve (2/3*1/2+1/4):1/3=

$$( \frac { 2 } { 3 } \cdot \frac { 1 } { 2 } + \frac { 1 } { 4 } ) : \frac { 1 } { 3 } =$$

Evaluate

$$\frac{7}{4}=1.75$$

Solution Steps

Multiply \frac{2}{3} times \frac{1}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\frac{2\times 1}{3\times 2}+\frac{1}{4}}{\frac{1}{3}}$$

Cancel out 2 in both numerator and denominator.

$$\frac{\frac{1}{3}+\frac{1}{4}}{\frac{1}{3}}$$

Least common multiple of 3 and 4 is 12. Convert \frac{1}{3} and \frac{1}{4} to fractions with denominator 12.

$$\frac{\frac{4}{12}+\frac{3}{12}}{\frac{1}{3}}$$

Since \frac{4}{12} and \frac{3}{12} have the same denominator, add them by adding their numerators.

$$\frac{\frac{4+3}{12}}{\frac{1}{3}}$$

Add 4 and 3 to get 7.

$$\frac{\frac{7}{12}}{\frac{1}{3}}$$

Divide \frac{7}{12} by \frac{1}{3} by multiplying \frac{7}{12} by the reciprocal of \frac{1}{3}.

$$\frac{7}{12}\times 3$$

Express \frac{7}{12}\times 3 as a single fraction.

$$\frac{7\times 3}{12}$$

Multiply 7 and 3 to get 21.

$$\frac{21}{12}$$

Reduce the fraction \frac{21}{12} to lowest terms by extracting and canceling out 3.

$$\frac{7}{4}$$

Factor

$$\frac{7}{2 ^ {2}} = 1\frac{3}{4} = 1.75$$