Solve (2/3+4/6)^2*6^2/12^2

$$( \frac { 2 } { 3 } + \frac { 4 } { 6 } ) ^ { 2 } \cdot \frac { 6 ^ { 2 } } { 12 ^ { 2 } }$$

Evaluate

$$\frac{4}{9}\approx 0.444444444$$

Solution Steps

Reduce the fraction \frac{4}{6} to lowest terms by extracting and canceling out 2.

$$\left(\frac{2}{3}+\frac{2}{3}\right)^{2}\times \frac{6^{2}}{12^{2}}$$

Add \frac{2}{3} and \frac{2}{3} to get \frac{4}{3}.

$$\left(\frac{4}{3}\right)^{2}\times \frac{6^{2}}{12^{2}}$$

Calculate \frac{4}{3} to the power of 2 and get \frac{16}{9}.

$$\frac{16}{9}\times \frac{6^{2}}{12^{2}}$$

Calculate 6 to the power of 2 and get 36.

$$\frac{16}{9}\times \frac{36}{12^{2}}$$

Calculate 12 to the power of 2 and get 144.

$$\frac{16}{9}\times \frac{36}{144}$$

Reduce the fraction \frac{36}{144} to lowest terms by extracting and canceling out 36.

$$\frac{16}{9}\times \frac{1}{4}$$

Multiply \frac{16}{9} and \frac{1}{4} to get \frac{4}{9}.

$$\frac{4}{9}$$

Factor

$$\frac{2 ^ {2}}{3 ^ {2}} = 0.4444444444444444$$