Solve (2/3+3/5)*1/2=

$$( \frac { 2 } { 3 } + \frac { 3 } { 5 } ) \cdot \frac { 1 } { 2 } =$$

Evaluate

$$\frac{19}{30}\approx 0.633333333$$

Solution Steps

Least common multiple of 3 and 5 is 15. Convert \frac{2}{3} and \frac{3}{5} to fractions with denominator 15.

$$\left(\frac{10}{15}+\frac{9}{15}\right)\times \frac{1}{2}$$

Since \frac{10}{15} and \frac{9}{15} have the same denominator, add them by adding their numerators.

$$\frac{10+9}{15}\times \frac{1}{2}$$

Add 10 and 9 to get 19.

$$\frac{19}{15}\times \frac{1}{2}$$

Multiply \frac{19}{15} times \frac{1}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{19\times 1}{15\times 2}$$

Do the multiplications in the fraction \frac{19\times 1}{15\times 2}.

$$\frac{19}{30}$$

Factor

$$\frac{19}{2 \cdot 3 \cdot 5} = 0.6333333333333333$$