Solve (2/2)^{2}-5^2*5^3-10^0+(5*8)^2

$$( \frac { 2 } { 2 } ) ^ { 2 } - 5 ^ { 2 } \times 5 ^ { 3 } - 10 ^ { 0 } + ( 5 \cdot 8 ) ^ { 2 }$$

Evaluate

$$-1525$$

Solution Steps

Divide 2 by 2 to get 1.

$$1^{2}-5^{2}\times 5^{3}-10^{0}+\left(5\times 8\right)^{2}$$

To multiply powers of the same base, add their exponents. Add 2 and 3 to get 5.

$$1^{2}-5^{5}-10^{0}+\left(5\times 8\right)^{2}$$

Calculate 1 to the power of 2 and get 1.

$$1-5^{5}-10^{0}+\left(5\times 8\right)^{2}$$

Calculate 5 to the power of 5 and get 3125.

$$1-3125-10^{0}+\left(5\times 8\right)^{2}$$

Subtract 3125 from 1 to get -3124.

$$-3124-10^{0}+\left(5\times 8\right)^{2}$$

Calculate 10 to the power of 0 and get 1.

$$-3124-1+\left(5\times 8\right)^{2}$$

Subtract 1 from -3124 to get -3125.

$$-3125+\left(5\times 8\right)^{2}$$

Multiply 5 and 8 to get 40.

$$-3125+40^{2}$$

Calculate 40 to the power of 2 and get 1600.

$$-3125+1600$$

Add -3125 and 1600 to get -1525.

$$-1525$$

Factor

$$-1525$$